| /* Timeout API for single-threaded programs that use blocking | |
| * syscalls (read/write/send/recv/connect/accept). | |
| * | |
| * Copyright (C) 2017 Red Hat, Inc. | |
| * | |
| * Author: Stefan Hajnoczi <stefanha@redhat.com> | |
| * | |
| * This program is free software; you can redistribute it and/or | |
| * modify it under the terms of the GNU General Public License | |
| * as published by the Free Software Foundation; version 2 | |
| * of the License. | |
| */ | |
| /* Use the following pattern: | |
| * | |
| * timeout_begin(TIMEOUT); | |
| * do { | |
| * ret = accept(...); | |
| * timeout_check("accept"); | |
| * } while (ret < 0 && ret == EINTR); | |
| * timeout_end(); | |
| */ | |
| #include <stdlib.h> | |
| #include <stdbool.h> | |
| #include <unistd.h> | |
| #include <stdio.h> | |
| #include "timeout.h" | |
| static volatile bool timeout; | |
| /* SIGALRM handler function. Do not use sleep(2), alarm(2), or | |
| * setitimer(2) while using this API - they may interfere with each | |
| * other. | |
| */ | |
| void sigalrm(int signo) | |
| { | |
| timeout = true; | |
| } | |
| /* Start a timeout. Call timeout_check() to verify that the timeout hasn't | |
| * expired. timeout_end() must be called to stop the timeout. Timeouts cannot | |
| * be nested. | |
| */ | |
| void timeout_begin(unsigned int seconds) | |
| { | |
| alarm(seconds); | |
| } | |
| /* Exit with an error message if the timeout has expired */ | |
| void timeout_check(const char *operation) | |
| { | |
| if (timeout) { | |
| fprintf(stderr, "%s timed out\n", operation); | |
| exit(EXIT_FAILURE); | |
| } | |
| } | |
| /* Stop a timeout */ | |
| void timeout_end(void) | |
| { | |
| alarm(0); | |
| timeout = false; | |
| } |