netfilter: move route indirection to struct nf_ipv6_ops
We cannot make a direct call to nf_ip6_route() because that would result
in autoloading the 'ipv6' module because of symbol dependencies.
Therefore, define route indirection in nf_ipv6_ops where this really
belongs to.
For IPv4, we can indeed make a direct function call, which is faster,
given IPv4 is built-in in the networking code by default. Still,
CONFIG_INET=n and CONFIG_NETFILTER=y is possible, so define empty inline
stub for IPv4 in such case.
Signed-off-by: Pablo Neira Ayuso <pablo@netfilter.org>
diff --git a/net/netfilter/utils.c b/net/netfilter/utils.c
index ca6d8d6..45c2241 100644
--- a/net/netfilter/utils.c
+++ b/net/netfilter/utils.c
@@ -48,3 +48,24 @@ __sum16 nf_checksum_partial(struct sk_buff *skb, unsigned int hook,
return csum;
}
EXPORT_SYMBOL_GPL(nf_checksum_partial);
+
+int nf_route(struct net *net, struct dst_entry **dst, struct flowi *fl,
+ bool strict, unsigned short family)
+{
+ const struct nf_ipv6_ops *v6ops;
+ int ret = 0;
+
+ switch (family) {
+ case AF_INET:
+ ret = nf_ip_route(net, dst, fl, strict);
+ break;
+ case AF_INET6:
+ v6ops = rcu_dereference(nf_ipv6_ops);
+ if (v6ops)
+ ret = v6ops->route(net, dst, fl, strict);
+ break;
+ }
+
+ return ret;
+}
+EXPORT_SYMBOL_GPL(nf_route);
